Complete the following reaction sequence for the chlorination of methane:
(N/A) The reaction of methane with chlorine in the presence of ultraviolet light $(hv)$ or at high temperatures $(573-773 \ K)$ proceeds via a free radical mechanism,leading to the successive replacement of hydrogen atoms by chlorine atoms:
$CH_4$ $\xrightarrow{hv, Cl_2, -HCl} CH_3Cl$ $\xrightarrow{hv, Cl_2, -HCl} CH_2Cl_2$ $\xrightarrow{hv, Cl_2, -HCl} CHCl_3$ $\xrightarrow{hv, Cl_2, -HCl} CCl_4$
$CH_4$ $\xrightarrow{hv, Cl_2, -HCl} CH_3Cl$ $\xrightarrow{hv, Cl_2, -HCl} CH_2Cl_2$ $\xrightarrow{hv, Cl_2, -HCl} CHCl_3$ $\xrightarrow{hv, Cl_2, -HCl} CCl_4$
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